K Fachtóirí-Sampla
Heics caipín Scriú 1/2 - 13 since plátáilte grád 5
Ag baint úsáide as chasmhóiminte = K x d x F K = .20
d = 0.50 in.
F = (75 faoin gcéad de the cruthúnais load) = 0.75 x 85,000 pise x 0.1419 cearn.in = 9045 lbs.
T = (0.20) (0.5 in.) (9045 lbs.) T= 905 in.-lbs. = 75 ft.-lbs.
I an roimhe example, againn mheas K = 0.20. seo tá a comhmmar K fachtóir le haghaidh since-plátáilte dúntóirí.
We must anois ionadh Cad may agat tharla dá an person shuiteáil an ceanglóir bheadh agat ró-lubricated the bolt agus instoptha leis the same torque. I den sórt sin coinníollacha, K may titim chun a value de 0.10.
Dá T = K x d x F, thga againn féidir freisin dhíspreagadhmine an réamhluchtaigh, F, isteach an sambealach.
F = T / (K x d)
F = 905 in.-lbs. / (0.10 x 0.50 in.) = 18,100 lbs.
Tá an luach faighte le haghaidh ár réamhluchtaigh, 18,100 lb., would dul thar an teanntachta neart de a 1/2 - 13 grád 5
bolta.Moath than likeilí the bolta isteach ceist bheadh agat theip. Tá an os coinne cruinnmtá freisin tharla resulting isteach a lower clamp load than maybe athcuired athulting isteach cluain teipuath.
